Consider the nuclear reaction $$3Li7+1H1$$→$$2$$ $$2He4$$ . The relevant atomic masses are $$7Li=7.018$$ amu, $$1H=1.0080$$, $$4He=4.004$$ amu . $$0.5$$ gms of $$1H1$$ completely consumed in the reaction along with sufficient amount of $$7Li$$ . Find energy released.

Question

Consider the nuclear reaction  $$3Li7+1H1$$→$$2$$ $$2He4$$ . The relevant atomic masses are  $$7Li=7.018$$ amu, $$1H=1.0080$$, $$4He=4.004$$ amu . $$0.5$$ gms of  $$1H1$$  completely consumed in the reaction along with sufficient amount of  $$7Li$$ . Find energy released.

Infinity Learn · Accepted Answer

Mass Defect $$=Reactants$$ $$-$$ Products ⇒Δ$$M=7.018+1.008$$ $$-2(4.004)$$ ⇒Δ$$M=0.018$$ amu Energy released per $$atom=$$ Δ$$Mc2=0.018$$×$$1.67$$×$$10$$−$$27$$×$$3$$×$$1082=2.7$$×$$10$$−$$12J$$  Now, in reaction hydrogen is limiting reagent. ∴Moles of hydrogen consumed $$=massMolar$$ $$mass=0.51=0.5$$ mol Number of atoms of hydrogen consumed $$=moles$$×NA $$=0.5$$ ×$$6.023$$×$$1023=$$ $$3.0115$$×$$1023$$  Hence, energy released in reaction $$=$$  $$3.0115$$×$$1023$$ ×$$2.7$$×$$10$$−$$12=8.1$$×$$1011J$$

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Consider the nuclear reaction 3Li7+1H1→2 2He4 . The relevant atomic masses are 7Li=7.018 amu, 1H=1.0080, 4He=4.004 amu . 0.5 gms of 1H1 completely consumed in the reaction along with sufficient amount of 7Li . Find energy released.

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