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Q.

Consider 3rd orbit of He+ (Helium) Using non relativistic approach, the speed of electron in this orbit will be (given K = 9 × 109 constant, Z = 2 and h= 6.6×10-34 Js) (Plancks constant=h)

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a

0.73 × 106 m/s

b

3.0 × 108 m/s

c

2.92 × 106 m/s

d

1.46 × 106 m/s

answer is D.

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Detailed Solution

We know that velocity V=e24πKh2n=1.6 x 10-1924 x 227 x 9 x 109 x 6.6 x 10-34 x 23 =1.46 x 106 ; (shortcut)  V=c137zn =3 x 108137 x 23=2137 x 108=1.46 x 106
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