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The displacement of two identical particles executing SHM are represented by equations \large {x_1}\, = \,4\sin \left( {10t + \frac{\pi }{2}} \right)\,\& \,{x_2}\, = \,5\cos \left( {\omega t} \right). For what value of \large \omega, energy of both the particles is same.

a
4 rad/s
b
8 rad/s
c
16 rad/s
d
32 rad/s

detailed solution

Correct option is B

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