1728 drops of mercury of equal radii possessing equal charges combine to from a big drop. Then the capacitance of bigger drop compared to each individual small drop is____times.
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answer is 0012.00.
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Detailed Solution
Volume of 1728 small drops =Volume of big drop ⇒1728×43πr3=43πR3 ⇒R=12r ⇒Also, C'=4πε0R, C=4πε0r ⇒C'C=Rr=12