First slide
Redistribution of charges and concept of common potential
Question

1728 drops of mercury of equal radii possessing equal charges combine to from a big drop. Then the capacitance of bigger drop compared to each individual small drop is____times. 

Easy
Solution

Volume of 1728 small drops =Volume of big drop 1728×43πr3=43πR3 R=12r  Also, C'=4πε0R, C=4πε0r C'C=Rr=12 

Get Instant Solutions
When in doubt download our app. Now available Google Play Store- Doubts App
Download Now
Doubts App