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Questions on calorimetry without phase change
Question

An electrically heated coil is immersed in a calorimeter containing 360 gm of water at 100C. The coil consumes energy at the rate of 90W. The water equivalent of the calorimeter and coil is 40 gm. The temperature of water after 10 min is

Moderate
Solution

energy given by heater=P×t=90×10×60 J

heat absorbed by water and calorimeter system is =( M+Mc) Sw(t-10)

90×60×10=400×10-3×4200 (t-10)

t= 42.14C  0

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