An electromagnetic wave of frequency v = 3.0 MHz passes from vacuum into a dielectric medium with relative permittivity ∈= 4.0. Then
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
Wavelength is doubled and frequency becomes half.
b
Wavelength is halved and frequency remains unchanged.
c
Wavelength and frequency both remain unchanged.
d
Wavelength is doubled and frequency unchanged.
answer is B.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Frequency of electromagnetic wave does not change with change in medium but wavelength and velocity of wave changes with change in medium. Velocity of electromagnetic wave in vacuumc=1μ0∈0=vλvacuum ......(i)Velocity of electromagnetic wave in the mediumvmedium =1μ0μr∈0ϵr=cμr∈rwhere μr and ϵr be relative permeability and relative permittivity of the medium. For dielectric medium, μr=1 Here, ∈r=4.0 ∴ vmedium =cϵr .........(ii) Wavelength of the wave in medium λmedium =vmedium v=c2v=λvacuum 2( Using (i) and (ii))