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An electron is an excited state of  Li2+ ion has angular momentum 3h/2π .The de Broglie wavelength of the electron in this state is  ρπa0(where a0 is the Bohr radius). The value of  ρ is

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answer is 2.

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Detailed Solution

Angular Momentum=nh2π=3h2π given ∴n=3Radius of nth orbit is rn=n2 a0zdeBroglie wavelength,  λelectron =hmv=ρπa0 ⇒mv=hρπa0Angular Momentum, mvrn=hρπa0a0 n2Z=3h2πPut n=3 ; Z=3⇒ρ=2
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An electron is an excited state of  Li2+ ion has angular momentum 3h/2π .The de Broglie wavelength of the electron in this state is  ρπa0(where a0 is the Bohr radius). The value of  ρ is