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Questions  

The energy required to ionize a hydrogen like ion in its ground state is 9 Rydberg. What is the wavelength of the radiation emitted when the electron In this ion jumps from the second excited state to the ground state?

a
24.2nm
b
35.8nm
c
8.6nm
d
11.4nm

detailed solution

Correct option is D

Rydberg energy=13.6 eV. So, ionization energy=  13.6z2eV=9×13.6eV⇒Z=3    When electron jumps from orbit 3 to 1,  1λ=RZ21n12−1n22      ⇒1λ=1.09×107×911−132          ⇒λ=11.4nm

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