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Q.

The energy required to ionize a hydrogen like ion in its ground state is 9 Rydberg. What is the wavelength of the radiation emitted when the electron In this ion jumps from the second excited state to the ground state?

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a

24.2nm

b

35.8nm

c

8.6nm

d

11.4nm

answer is D.

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Detailed Solution

Rydberg energy=13.6 eV. So, ionization energy=  13.6z2eV=9×13.6eV⇒Z=3    When electron jumps from orbit 3 to 1,  1λ=RZ21n12−1n22      ⇒1λ=1.09×107×911−132          ⇒λ=11.4nm
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