In an excited hydrogen atom, when the electron jumps from nth energy level to (n-1)th energy level, wavelength of emitted radiation is λ, when the electron jumps from (n-1)th energy level to (n-2)th energy level, wavelength of emitted radiation is Kλ. Then what will be the wavelength of emitted radiation when the electron jumps from nth energy level to (n-2)th energy level?
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a
KλK+1
b
K2λK+1
c
λK+1
d
K-1K+1λ
answer is A.
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Detailed Solution
hcλ=13.61n−12−1n2hcKλ=13.61n−12−1n−22∴ and hcλ1=13.61n−22−1n2∴ hcλ1=13.61n−22−1n−12+13.61n−12−1n2⇒hcλ1=hcKλ+hcλ⇒λ1=KλK+1