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Figure shows the adiabatic curve for n moles of an ideal gas; the bulk's modulus for the gas corresponding to the point P will be

a
nR(1+2T0V0)
b
nR(2+T0V0)
c
nR(1+T0V0)
d
nR(1+T02V0)

detailed solution

Correct option is C

Bulk's modulus K = -dPdVV = γP [PVγ = constant]For the curve TVγ-1 = k (constant)or V dT + T(γ-1)dV = 0or dVdT = -V(γ-1)T = -1       (slope at point P)∴ γ = 1+V0T0∴ K = γ[nRT0V0] = nR(1+T0V0)

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