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A fixed mass of helium gas is made to undergo a process in which its pressure varies linearly from 1 kPa to 2 kPa, in relation to its volume as the latter varies from 0.2 m3 to 0.4 m3. The heat absorbed by the gas will be

a
300 J
b
900 J
c
1200 J
d
1500 J

detailed solution

Correct option is C

∆W =1 + 2 × 103N/m2× 0.4 – 0.2m3= 300 JΔU = nCV∆T =(P2V2−P1V1)γ−1= 3/2 0.4 × 2 − 0.2 × 1 × 103 J = 900 J                       ΔQ =ΔW +ΔU = 1200 J

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