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The focal length of spherical mirror is given by $f = \frac{R}{2}$ when R is the radius of curvature of the mirror. For a given spherical mirror made of steel the focal length is f= 24.0 cm. What is the new focal length if temperature is increased by 50°C? $(Given α_{steel} = 12 \times 10^{- 5} / C)$

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24.144 cm

20.0144 cm

28.0288 cm

44.144 cm

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detailed solution

Correct option is A

Δl=(1+αΔT)Rf=R1+12×10−5×50Rf=481+600×10−5Rf=48(1+0.006)Rf=48(1.006)Rf=48.288f=R2f=24.144cm

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The focal length of spherical mirror is given by f=R2 when R is the radius of curvature of the mirror. For a given spherical mirror made of steel the focal length is f= 24.0 cm. What is the new focal length if temperature is increased by 50°C? Given αsteel =12×10−5/C

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Ready to Test Your Skills?

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