A force of $$25$$ N acts on a body at rest for $$0.2$$ s and a force of $$70$$ N acts for the next $$0.1$$ s in opposite direction. If the final velocity of the body is $$5$$ ms–$$1$$ in opposite direction, the mass of the body is

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Infinity Learn · Accepted Answer

F $$=$$ $$P/tP1$$ $$=$$ $$F1t1$$ $$=$$ $$25$$ x $$0.2$$ $$=$$ $$5$$ $$kg-m/sP2$$ $$=$$ $$F2t2$$ $$=$$ $$(-70)$$ x $$0.1$$ $$=$$ $$-7$$ $$kg-m/sNet$$ impulse $$=$$ $$(-7)$$ $$+$$ $$5$$ $$kg-m/s$$ $$=$$ $$-2$$ $$kg-m/sNow$$, mvf $$-$$ mvi $$=$$ Net impulse∴ m x $$(-5)$$ $$-$$ $$0$$ $$=$$ $$-2$$ ⇒ m $$=$$ $$0.4$$ kg

A force of 25 N acts on a body at rest for 0.2 s and a force of 70 N acts for the next 0.1 s in opposite direction. If the final velocity of the body is 5 ms^–1 in opposite direction, the mass of the body is

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A force of 25 N acts on a body at rest for 0.2 s and a force of 70 N acts for the next 0.1 s in opposite direction. If the final velocity of the body is 5 ms–1 in opposite direction, the mass of the body is

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A force of 25 N acts on a body at rest for 0.2 s and a force of 70 N acts for the next 0.1 s in opposite direction. If the final velocity of the body is 5 ms^–1 in opposite direction, the mass of the body is