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Q.

A force of 25 N acts on a body at rest for 0.2 s and a force of 70 N acts for the next 0.1 s in opposite direction. If the final velocity of the body is 5 ms–1 in opposite direction, the mass of the body is

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a

1 kg

b

2 kg

c

0.8 kg

d

0.4 kg

answer is D.

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Detailed Solution

F = P/tP1 = F1t1 = 25 x 0.2 = 5 kg-m/sP2 = F2t2 = (-70) x 0.1 = -7 kg-m/sNet impulse = (-7) + 5 kg-m/s = -2 kg-m/sNow, mvf - mvi = Net impulse∴ m x (-5) - 0 = -2 ⇒ m = 0.4 kg
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A force of 25 N acts on a body at rest for 0.2 s and a force of 70 N acts for the next 0.1 s in opposite direction. If the final velocity of the body is 5 ms–1 in opposite direction, the mass of the body is