Questions
10 g of ice at 0°C is mixed with 100 g of water at 50°C. What is the resultant temperature of mixture?
detailed solution
Correct option is D
10×80+10×1×θ-0=100×1×50-θ⇒θ=38.18oC.Talk to our academic expert!
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10 g of ice at -20°C is dropped into a calorimeter containing 10 g of water at l 0°C; the specific heat _of water is twice that of ice . When equilibrium is reached,· the calorimeter will contain:
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