First slide

First law of thermodynamics

Question

A gas is compressed at a constant pressure of 50 N/m² from a volume 10m³ to a volume of 4m³. 100J of heat is added to the gas then its internal energy

Easy

A

Increases by 400J
B

Increases by 200J
C

Decreases by 400J
D

Decreases by 200J

Solution

$P = 50N/{m^2}:{V_1} = 10{m^3},{V_2} = 4{m^3}$
$\Delta Q = 100J,\Delta U = ?$
$\Delta U = \Delta Q - \Delta U$
$\Delta W = p({v_2} - {v_1}) = 50(4 - 10) = - 300J$
$\Delta U = 100 - ( - 300) = 400J\,\,increases$

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