Questions
A homogenous rod of length and mass M is lying on a smooth horizontal floor. A bullet of mass m hits the rod at a distance x from the middle of the rod at a velocity v0 perpendicular to the rod and comes to rest after collision. If the velocity of the farther end of the rod just after the impact is in the opposite direction of v0, then
detailed solution
Correct option is D
Let after collision velocity of rod be v and angular velocity be ω, thenmv0=mv+MV⇒mv0x=mvx+Mℓ212ωmv0=mv+Mωη2x12From above equations,Mωη2x12=MV⇒ωη2x=12V Velocity of farther end of the rod =V−lω2=ωη2x12−ωηx2=ωηx2η6−1If this velocity is opposite to v0, thenη6−1<0⇒η<6Talk to our academic expert!
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A boy stands over the centre of a horizontal platform which is rotating freely with a speed of 2 revolutions/s about a vertical axis through the centre of the platform and straight up through the boy. He holds 2 kg masses in each of his hands close to his body. The. combined moment of inertia of the system is 1 kgmetre2. The boy now stretches his arms so as to hold the masses far from his body. In this situation, the moment of inertia of the system increases to 2kgmetre2. The kinetic energy of the system in the latter case as compared with that in the previous case will
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