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A homogenous rod of length l=ηx and mass M is lying on a smooth horizontal floor. A bullet of mass m hits the rod at a distance x from the middle of the rod at a velocity v0 perpendicular to the rod and comes to rest after collision.  If the velocity of the farther end of the rod just after the impact is in the opposite direction of v0, then 

 

a
η>3
b
η<3
c
η>6
d
η<6

detailed solution

Correct option is D

Let after collision velocity of rod be v and angular velocity be ω, thenmv0=mv+MV⇒mv0x=mvx+Mℓ212ωmv0=mv+Mωη2x12From above equations,Mωη2x12=MV⇒ωη2x=12V Velocity of farther end of the rod =V−lω2=ωη2x12−ωηx2=ωηx2η6−1If this velocity is opposite to v0, thenη6−1<0⇒η<6

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