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In hydrogen and hydrogen-like atoms, the ratio of $E_{4 n} - E_{2 n}$ and $E_{2 n} - E_{n}$ varies with atomic number z and principal quantum number n as

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detailed solution

Correct option is D

E4n−E2nE2n−En=E116n2−E14n2E14n2−E1n2=14= constant

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In hydrogen and hydrogen-like atoms, the ratio of E4n−E2n and E2n−En varies with atomic number z and principal quantum number n as

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Ready to Test Your Skills?

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In hydrogen and hydrogen-like atoms, the ratio of $E_{4 n} - E_{2 n}$ and $E_{2 n} - E_{n}$ varies with atomic number z and principal quantum number n as