An ideal gas is found to obey the relation PV32= constant during an adiabatic process. If such a gas initially at a temperature T is compressed to half of initial volume, then its final temperature will be
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a
2T
b
2T
c
22T
d
4T
answer is B.
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Detailed Solution
PV32=constant ⇒γ=32 so from T1V1γ-1=T2V2γ-1 We have T2=T1V1V212=TVV/212=2T