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An ideal gas is found to obey the relation = constant during an adiabatic process. If such a gas initially at a temperature T is compressed to half of initial volume, then its final temperature will be
detailed solution
Correct option is B
PV32=constant ⇒γ=32 so from T1V1γ-1=T2V2γ-1 We have T2=T1V1V212=TVV/212=2TTalk to our academic expert!
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During an adiabatic process, the pressure of a gas is found to be proportional to the cube of its temperature. The ratio of for the gas is
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