An ideal gas has pressure P at absolute temperature T. Its pressure is increased by ΔP due to an increase in temperature ΔT. If the volume of the gas remains constant, the fractional change in pressure per unit rise in temperature $$($$Δ$$P/P)/$$ΔT is proportional to

Question

An ideal gas has pressure P at absolute temperature T. Its pressure is increased by ΔP due to an increase in temperature ΔT. If the volume of the gas remains constant, the fractional change in pressure per unit rise in temperature $$($$Δ$$P/P)/$$ΔT is proportional to

Infinity Learn · Accepted Answer

As the gas is ideal: PV $$=$$ nTR , and here V, n and R are constants. Hence if T changes, P changes. Introducing changes we get $$V(P+$$Δ$$P)$$ $$=$$ $$n(T+$$Δ$$T)R$$. From this subtract PV $$=$$ nTR  and manipulate for the quantity $$($$Δ$$P/P)/$$ΔT

An ideal gas has pressure P at absolute temperature T. Its pressure is increased by $ΔP$ due to an increase in temperature $ΔT$ . If the volume of the gas remains constant, the fractional change in pressure per unit rise in temperature $(ΔP / P) / ΔT$ is proportional to

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An ideal gas has pressure P at absolute temperature T. Its pressure is increased by ΔP due to an increase in temperature ΔT. If the volume of the gas remains constant, the fractional change in pressure per unit rise in temperature (ΔP/P)/ΔT is proportional to

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Ready to Test Your Skills?

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An ideal gas has pressure P at absolute temperature T. Its pressure is increased by $ΔP$ due to an increase in temperature $ΔT$ . If the volume of the gas remains constant, the fractional change in pressure per unit rise in temperature $(ΔP / P) / ΔT$ is proportional to