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Q.

An ideal gas heat engine operates in carnot’s cycle between 227oc  and  127oc.      If absorbs 6×104 cals  of heat at higher temperature amount of heat converted to work is

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a

4.8×104 cals

b

1.2×104 cals

c

2.4×104 cals

d

6×104 cals

answer is B.

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Detailed Solution

Temperature T1=227+273=500 K (converting degree celsius into kelvin)  :T2=127+273=400 K  effieciency of heat engine is  η=1-T2T1---(1)  substitute given temperatures in equation (1) ⇒η=1-400500 ⇒ η=15---(2)  also efficiency is  η=Work done (w)heat given to engine(Q)---(3)substitute given Q=6×104calorie, and equation (2) in (3) ⇒15=W6×104  W=6×1045  W=1.2×104 calamount of heat converted to work =1.2×104 cal
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