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An ideal gas is initially at temperature T and volume V. Its volume is increased by $∆ V$ due to an increase in temperature $∆ T$ , pressure remaining constant. The quantity
$δ = (ΔV / VΔT)$ varies with temperature as

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detailed solution

Correct option is C

We know that V/T = constant∴ ΔVV=−ΔTT or ΔVVΔT=−1T or δ=−1TSo, the graph between δand T is a rectangular hyperbola with negative slope.

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An ideal gas is initially at temperature T and volume V. Its volume is increased by ∆V due to an increase in temperature ∆T, pressure remaining constant. The quantityδ=(ΔV/VΔT) varies with temperature as

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An ideal gas is initially at temperature T and volume V. Its volume is increased by $∆ V$ due to an increase in temperature $∆ T$ , pressure remaining constant. The quantity
$δ = (ΔV / VΔT)$ varies with temperature as