First slide

Work done by gas

Question

An ideal gas is taken through the cycle A ➔ B ➔ C ➔ A, as shown in the figure. If the net heat supplied to the gas in the cycle is 5 J, the work done by the gas in the process C ➔ A is:

Easy

A

- 5 J
B

-10 J
C

-15 J
D

-20 J

Solution

$Q = W + ∆ U \Rightarrow W_{cycle} = Q - ∆ U = 5 - 0 = 5 J But T_{cycle} = W_{AB} + W_{BC} + W_{CA} So, 5 = 10 (2 - 1) + 0 + WCA \Rightarrow W_{CA} = - 5 J$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App