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An ideal gas is taken through a cyclic thermodynamical process through four steps. Amounts of heat involved in these steps are : Q1 = 5960 J, Q2 = -5585 J, Q3 = -2980 J and Q4 = 3645 J respectively. The corresponding works involved are : W1 = 2200 J, W2 = - 825 J, W3 = -1100 J and W4 respectively. Value of W4 is:
 

a
275 J
b
675 J
c
765 J
d
1315 J

detailed solution

Correct option is C

For cyclic process ∆U=0 ⇒     W4=Q1+Q2+Q3+Q4-W1-W2-W3                 =765 J

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In which process net work done is zero?
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