First slide

Work done by gas

Question

An ideal gas is taken through a cyclic thermodynamical process through four steps. Amounts of heat involved in these steps are : Q₁ = 5960 J, Q₂ = -5585 J, Q₃ = -2980 J and Q₄ = 3645 J respectively. The corresponding works involved are : W₁ = 2200 J, W₂ = - 825 J, W₃ = -1100 J and W₄ respectively. Value of W₄ is:

Moderate

A

275 J
B

675 J
C

765 J
D

1315 J

Solution

For cyclic process
$∆ U = 0 \Rightarrow W_{4} = Q_{1} + Q_{2} + Q_{3} + Q_{4} - W_{1} - W_{2} - W_{3} = 765 J$

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