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Q.

If the displacement of a particle executing SHM is given by, y = 0.30 sin (220t +0.64) in meters, then the frequency and the maximum velocity of the particle is

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a

35 Hz, 66 m/s

b

45 Hz, 66 m/ s

c

58 Hz, 113 m/s

d

35 Hz, 132 m/s

answer is A.

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Detailed Solution

n=ω2π=2202π=35Hzvmax=ωa=220×0.30ms−1=66 ms-1
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