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Questions  

If the energy of a photon corresponding to a wavelength of 6000  is 3.32 x10-19  joule, the
photon energy (in joule) for a wavelength of 4000  will be

a
1.11 x10-19
b
2.22 x10-19
c
4.44 x 10-19
d
4.98 x 10 -19

detailed solution

Correct option is D

we know that E=hc/λE1=hcλ1  and  E2=hcλ2 or E2=E1×λ1λ2 =3⋅32×10−1960004000=3⋅32×10−19(3/2) =4.98×10−19 joule

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