If the wavelengths of the first line of the Lyman series for the hydrogen atom is 1210 Å  then the wavelength of the first line of the Balmer series of the hydrogen spectrum is

we know that 1λ=R1n12−1n22  ForfirstlineofLymanseries, n1=1 and n2=2∣ 1λ1=R11−14=3R4 or R=43λ1  ForfirstlienofBalmerseries n1=2 and n2=3 1λ2=R14−19=5R36=53643λ1 or 1λ2=536×43×11210 or λ2=36×3×12105×4=6534Å