Questions
If the wavelengths of the first line of the Lyman series for the hydrogen atom is 1210 then the wavelength of the first line of the Balmer series of the hydrogen spectrum is
detailed solution
Correct option is A
we know that 1λ=R1n12−1n22 ForfirstlineofLymanseries, n1=1 and n2=2∣ 1λ1=R11−14=3R4 or R=43λ1 ForfirstlienofBalmerseries n1=2 and n2=3 1λ2=R14−19=5R36=53643λ1 or 1λ2=536×43×11210 or λ2=36×3×12105×4=6534ÅSimilar Questions
Which of the following cannot be the energy of the electron in the hydrogen atom?
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