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Q.

An inductor of 2H and a resistance of 10 Ω are connected in series with a battery of 5 V. The initial rate of change of current is

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a

0.5 A/s

b

2.0 A/s

c

2.5 A/s

d

0.25 A/s

answer is C.

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Detailed Solution

i=i01−e−RtL⇒didt=ddti0−ddti0e−RtL⇒didt=0−i0−RLe−RtL=i0RLe−RtLInitially, t=0⇒didt=i0×RL=EL=52=2.5A/s
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