A lead ball moving with a velocity V strikes a wall and stops. If $$50$$% of its energy is converted into heat, then what will be increase in temperature? (specific$$ heat of lead is $$S)

Question

A lead ball moving with a velocity V strikes a wall and stops. If $$50$$% of its energy is converted into heat, then what will be increase in temperature? (specific$$ heat of lead is $$S)

Infinity Learn · Accepted Answer

from Joules lawwork done is converted to heat energy⇒$$W=JQ---(1)50$$% of moving energy $$=$$ $$50100xKE=W$$  (from$$ $$W=$$∆$$KE$$$$)W=50100x12mV2---(2)  here m is mass of the ball; V is velocity of ballheat energy $$Q=mSd$$θ$$----(3)$$  here S is specific heat;dθ is change in temperature  substitute equations (2),(3) in (1)  $$12(12mV2)=JmSd$$θ ⇒dθ$$=V24JSincrease$$ in temperature $$=V24JS$$

A lead ball moving with a velocity V strikes a wall and stops. If 50% of its energy is converted into heat, then what will be increase in temperature? (specific heat of lead is S)

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