A lead ball moving with a velocity V strikes a wall and stops. If 50% of its energy is converted into heat, then what will be increase in temperature? (specific heat of lead is S)

from Joules lawwork done is converted to heat energy⇒W=JQ---(1)50% of moving energy = 50100xKE=W  (from W=∆KE)W=50100x12mV2---(2)  here m is mass of the ball; V is velocity of ballheat energy Q=mSdθ----(3)  here S is specific heat;dθ is change in temperature  substitute equations (2),(3) in (1)  12(12mV2)=JmSdθ ⇒dθ=V24JSincrease in temperature =V24JS