First slide

laws

Question

250 litre of an ideal gas is heated at constant pressure from $27^{0} C$ such that its volume becomes 500 litres. The final temperature is

Easy

A

$54^{0} C$
B

$300^{0} C$
C

$327^{0} C$
D

$600^{0} C$

Solution

By Charles' law ,if V is doubled, T is also doubled.
$T_{1} = (27 + 273) K = 300 K$
$T_{2} = 2 \times 300 K = 600 K$
$t_{2} = {(600 - 273)}^{0} C = 327^{0} C$

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