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The mass of the liquid flowing per second per unit area of cross section of the tube is proportional to Px and vy , where P is the pressure difference and v is the velocity, then the relation between x and y is

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An Intiative by Sri Chaitanya

a

x=y

b

x=-y

c

y2=x

d

y=-x2

answer is B.

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Detailed Solution

MAt∝Pxvy⇒ ML−2T−1=ML−1T−2xL1T−1y⇒ ML−2T−1==MxL−x+yT−2x−yon comparing we get x=1,−x+y=−2, and −2x−y=−1From here, we get y = -1.Thus, x = -y.

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