1 mole of gas expands isothermally at 37° C. The amount of heat absorbed by it until its volume doubled is (R = 8.31 mol-1  K-1)

Here, T=37∘C=37+273=310 K, V2=2V1Work done in isothermal process isW=nRTln⁡V2V1=1×8.31×310×ln⁡2V1V1=8.31×310×ln⁡2=1.786×103JAmount of heat absorbed =1.786×1034.2cal=425.24 cal