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1 mole of gas expands isothermally at 37° C. The amount of heat absorbed by it until its volume doubled is (R = 8.31 mol-1  K-1

a
411.25cal
b
418.50cal
c
420.25cal
d
425.24 cal

detailed solution

Correct option is D

Here, T=37∘C=37+273=310 K, V2=2V1Work done in isothermal process isW=nRTln⁡V2V1=1×8.31×310×ln⁡2V1V1=8.31×310×ln⁡2=1.786×103JAmount of heat absorbed =1.786×1034.2cal=425.24 cal

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