1 mole of a monoatomic gas at temperature T0 expand slowly according to the law  P2  is proportional to  T . Its final temperature is 2T0, then heat supplied to the gas is

Given ,Number of moles=1 moleTemperature =T0From QuestionP2∝T⇒P=cT  ,  c is constant∴dPP=12dTT....1 PV=RT….(2)⇒PdV+VdP=RdT⇒PdV=RdT−VdP=RdT−RT⋅dPP=RdT−RT2dTT( by using (1))=RdT2∴∫T02T0 PdV=∫T02T0 RdT2=RT02 From first law of thermodynamicsQ=ΔU+W=nCVΔT+∫PdV=fnRT02+RT02=3(1)R2T0+RT02=2RT0                                                          Therefore, the correct answer is (D).