First slide
Kinetic theory of ideal gases
Question

The molecules of a given mass of a gas have RMS speed  200  ms1 at 27 ºC and 10Nm2  pressure. When the absolute temperature is doubled and the pressure is halved, then find RMS speed of the molecules of the same gas in  ms1 .

Moderate
Solution

vRMS=3RTM  (independent of pressure, for a given temperature).
vRMS  α   T v2v1=   T2T12T1T1=2 v2=2002 m/s.
 

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