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The molecules of a given mass of a gas have RMS speed $200 m s^{- 1}$ at 27 ºC and 10 $N m^{- 2}$ pressure. When the absolute temperature is doubled and the pressure is halved, then find RMS speed of the molecules of the same gas $(i n m s^{- 1})$ .

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detailed solution

Correct option is B

vRMS=3RTM (independent of pressure, for a given temperature).⇒vRMS α T v2v1= T2T1= 2T1T1=2 v2=2002 m/s.

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The molecules of a given mass of a gas have RMS speed 200 ms−1 at 27 ºC and 10Nm−2 pressure. When the absolute temperature is doubled and the pressure is halved, then find RMS speed of the molecules of the same gas in ms−1 .

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Ready to Test Your Skills?

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The molecules of a given mass of a gas have RMS speed $200 m s^{- 1}$ at 27 ºC and 10 $N m^{- 2}$ pressure. When the absolute temperature is doubled and the pressure is halved, then find RMS speed of the molecules of the same gas $(i n m s^{- 1})$ .