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The molecules of a given mass of a gas have r.m.s. velocity of 200 ms-1 at 27oC and 1.0 x 105 Nm-2 pressure. When the temperature and pressure of the gas are respectively, 1270C and 0.05 × 105 Nm-2, the r.m.s. velocity of its molecules in ms-l is:

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a
1002
b
4003
c
10023
d
1003

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detailed solution

Correct option is B

v ∝ T   ⇒ v200 = 400300 ⇒ v = 200×23m/s⇒ v = 4003m/s


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