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Q.

1 moles of diatomic gas at 27°C is heated at constant temperature, so that its volume is doubled.  If R = 8.3 J/mole/K.  Find the work done in this process

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a

1718 J

b

1500 J

c

1640 J

d

2490 J

answer is A.

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Detailed Solution

dW=nRTlnv2v1 =1×8.3×300ln2 =2500×0.69 =1718J
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