Questions
3 moles of mono atomic ideal gas are mixed with 2 moles of diatomic ideal gas. Then the ratio of of the mixture is
a
1715
b
2919
c
139
d
2719
detailed solution
Correct option is B
(2)'γm' =CPCV for mono atomic gas =3+23=53 Cp1=5R2, Cv1=3R2'γd' =CPCV for dia atomic gas =5+25=75 Cp2 =7R2 , Cv2= 5R2γ for the mixture n1Cp1+n2Cp2n1Cv1+n2Cv2=35R2+27R23 3R2+2 5R2=15+149+10=2919Talk to our academic expert!
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