3 moles of mono atomic ideal gas are mixed with 2 moles of diatomic ideal gas. Then the ratio of CPCV of the mixture is
1715
2919
139
2719
(2)
'γm' =CPCV for mono atomic gas =3+23=53 Cp1=5R2, Cv1=3R2'γd' =CPCV for dia atomic gas =5+25=75 Cp2 =7R2 , Cv2= 5R2γ for the mixture n1Cp1+n2Cp2n1Cv1+n2Cv2=35R2+27R23 3R2+2 5R2=15+149+10=2919