A monatomic ideal gas, initially at temperature T1, is enclosed in a cylinder fitted with a frictionless piston. The gas is allowed to expand adiabatically to a temperature T2 by releasing the piston suddenly. If L1 and L2 are the length of the gas column before and after expansion respectively, then T1T2is given by
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a
L1L22/3
b
L1L2
c
L2L1
d
L2L12/3
answer is D.
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Detailed Solution
Here TVγ−1= constant As γ=5/3,hence TV2/3= constant Now, T1L12/3=T2L22/3 (∵V∝L)or T1T2=L2L12/3