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A mono atomic gas is expanded from volume $V_{1}$ to volume $V_{2}$ according to the process $p V^{\frac{3}{2}} =$ constant. Then ratio of work done by the gas to the charge in its internal energy is

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Correct option is C

W=P1V1−P2V2(n−1)=μR(T1−T2)(n−1)ΔV=μCv.(T2−T1)=−μ3R2(T2−T2)∴ WΔV=μR(T1−T2)(32−1)×[−23μR(T1−T2)]=−43

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A mono atomic gas is expanded from volume V1 to volume V2 according to the process pV32=constant. Then ratio of work done by the gas to the charge in its internal energy is

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A mono atomic gas is expanded from volume $V_{1}$ to volume $V_{2}$ according to the process $p V^{\frac{3}{2}} =$ constant. Then ratio of work done by the gas to the charge in its internal energy is