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Q.

A mono atomic gas is expanded from volume V1 to volume V2 according to the process pV32=constant. Then ratio of work done by the gas to the charge in its internal energy is

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a

23

b

−13

c

−43

d

34

answer is C.

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Detailed Solution

W=P1V1−P2V2(n−1)=μR(T1−T2)(n−1)ΔV=μCv.(T2−T1)=−μ3R2(T2−T2)∴ WΔV=μR(T1−T2)(32−1)×[−23μR(T1−T2)]=−43
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