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A monoatomic gas at a pressure P, having a volume V expands isothermally to a volume 2V and then adiabatically to a volume 16V. The final pressure of the gas is :(take $γ$ = 5/3)

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64 P

32 P

P64

16 P

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detailed solution

Correct option is C

For isothermal process P1V1=P2V2⇒ PV=P2(2V) ⇒P2=P2For a adiabatic process P2V2γ=P3V3γ⇒ P2(2V)γ=P3(16V)γ ⇒ P3=321853=P64

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A monoatomic gas at a pressure P, having a volume V expands isothermally to a volume 2V and then adiabatically to a volume 16V. The final pressure of the gas is :(take γ = 5/3)

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A monoatomic gas at a pressure P, having a volume V expands isothermally to a volume 2V and then adiabatically to a volume 16V. The final pressure of the gas is :(take $γ$ = 5/3)