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Q.

Number of molecules in a volume of 4cm3 of a perfect mono atomic gas at some temperature T and at a pressure of 2cm of mercury is close to? (Given, mean kinetic energy of a molecule (at T) is 4×10−14 erg,g=980 cm/s2,density of mercury=13.6 g/cm3)

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a

5.8×1016

b

4.0×1016

c

4.0×1018

d

5.8×1018

answer is C.

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Detailed Solution

No of molecules=N=PVKTK=Boltzman Constant ​⇒N=2hρHggKT⇒N=24.13.698023K.E,      We know32KT=K.E⇒N= 3×13.6×98044×10−14 =4×1018
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