First slide
Second law
Question

An object flying in air with velocity 

\large (20\hat i + 25\hat j - 12\hat k)

suddenly breaks in two pieces whose masses are in the ratio 1 : 5. The smaller mass flies off with a velocity 

\large (100\hat i + 35\hat j + 8\hat k)

. The velocity of the larger piece will be :
 

Moderate
Solution

By conservation of linear momentum
\large {\vec P_i} = {\vec P_f}
\large m{\vec v_i} = \left( {\frac{m}{6}{{\vec v}_1} + \frac{{5m}}{6}{{\vec v}_2}} \right)
\large {\vec v_i} = \left( {\frac{{{{\vec v}_1}}}{6} + \frac{5}{6}{{\vec v}_2}} \right)
\large 20\hat i + 25\hat j - 12\hat k = \frac{{\left( {100\hat i + 35\hat j + 8\hat k} \right)}}{6} + \frac{{5{{\vec v}_2}}}{6}
\large 120\hat i + 150\hat j - 72\hat k = 100\hat i + 35\hat j + 8\hat k + 5{\vec v_2}
20\hat i + 115\hat j - 80\hat k = 5{\vec v_2}
\large {\vec v_2} = \frac{{20\hat i + 115\hat j - 80\hat k}}{5}
\large 4\hat i + 23\hat j - 16\hat k

Get Instant Solutions
When in doubt download our app. Now available Google Play Store- Doubts App
Download Now
Doubts App