Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

One end of a long iron chain of linear mass density  λ is fixed to a sphere of mass  m and specific density 1/3  while the other end is free. The sphere along with the chain is  immersed in a deep lake. If specific density of iron is 7, the height  h above the bed of the lake at which the sphere will float in equilibrium is xmλ.Find x. (Assume that the part of the chain lying on the bottom of the lake exerts negligible forces on the upper part of the chain)

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

answer is 2.33.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Weight of sphere + chain  =(m+λh)gBuoyant force  =ρLmρSg+ρLλhρCg=(3m+λh7)gFor equilibrium, weight=Buoyant forceOr,  m+λh=3m+λh7Or,  h=7m3λ
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring