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One mole of ideal gas goes through process  P=2V21+V2 then the change in temperature of gas when volume changes from v=1m3  to v=  2m3 is 

a
−45RK
b
−52RK
c
2K
d
115RK

detailed solution

Correct option is D

ideal gas equation is PV=nRT---(1)given P=2V21+V2;n=1;substitute in eqn (1)2V21+V2V=1XRT 2V31+V2R=T=temperature by question, V=1m3;substitute in above equation to get T1 temperature T1=22R=1R by question, V=2m3;substitute in above equation to get T2 T2=2X231+22R=165R T2−T1=165R−1R=115RKelvin

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