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Questions  

One mole of an ideal gas at an initial temperature of T K does 6 R joules of work adiabatically. If the ratio of specific heats of this gas at constant pressure and at constant volume is 53,the final temperature of gas will be :

a
(T - 2.4)K
b
(T+ 4)K
c
(T - 4)K
d
(T + 2.4)K

detailed solution

Correct option is C

Q=0⇒∆U=-6R=(1)R∆Tγ-1=32R∆T ⇒                  ∆T=-4 ⇒                    Tf=(T-4)K

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