First slide

Bohr Model of the Hydrogen atom.

Question

An orbital electron in the ground state of hydrogen has an angular momentum $L_{1}$ , and an orbital electron in the first excited state in doubly ionized Lithium has an angular momentum $L_{2}$ . Then

Easy

A

$L_{1} = L_{2}$
B

$L_{2} = \frac{3 L_{1}}{2}$
C

$L_{2} = \frac{2 L_{1}}{3}$
D

$L_{2} = 2 L_{1}$

Solution

$L = \frac{n h}{2 π}$ for all 1st orbit it is $\frac{h}{2 π}$
For all 2nd orbit is $\frac{2 h}{2 π}$

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