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An orbital electron in the ground state of hydrogen has an angular momentum $L_{1}$ , and an orbital electron in the first excited state in doubly ionized Lithium has an angular momentum $L_{2}$ . Then

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L1= L2

L2 = 3L12

L2 = 2L13

L2 = 2L1

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detailed solution

Correct option is D

L = nh2π for all 1st orbit it is h2π For all 2nd orbit is 2h2π

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An orbital electron in the ground state of hydrogen has an angular momentum L1 , and an orbital electron in the first excited state in doubly ionized Lithium has an angular momentum L2 . Then

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

An orbital electron in the ground state of hydrogen has an angular momentum $L_{1}$ , and an orbital electron in the first excited state in doubly ionized Lithium has an angular momentum $L_{2}$ . Then