An orbital electron in the ground state of hydrogen has an angular momentum L1 , and an orbital electron in the first excited state in doubly ionized Lithium has an angular momentum L2 . Then
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a
L1= L2
b
L2 = 3L12
c
L2 = 2L13
d
L2 = 2L1
answer is D.
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Detailed Solution
L = nh2π for all 1st orbit it is h2π For all 2nd orbit is 2h2π