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In order to increase the volume of a gas to 3 times at constant pressure at $40^{o} C$ , the final temperature should be

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6660C

7770C

5550C

3330C

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detailed solution

Correct option is A

T'T = 3VV = 3 T' = 3T = 3[40+273]K = 3 × 313 K = 939 K T = (939-273)0C = 6660C

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In order to increase the volume of a gas to 3 times at constant pressure at 40oC, the final temperature should be

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In order to increase the volume of a gas to 3 times at constant pressure at $40^{o} C$ , the final temperature should be