Path of a particle moving in x-y plane is y = 3x + 4. At some instant suppose x-component of velocity is 1 m/s and it is increasing at a constant rate of 1 m/s2. Then, at this instant

y=3x+4 Differentiating wrt time vy=3vx=31=3 ms-1 Differentiating wrt time ay=3ax=31=3 ms-2 now, vnet=vx2+vy2=10ms-1 anet=ax2+ay2=10ms-2Acceleration is constant . So v-t curve will be straight line.