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In a potentiometer experiment, the balancing with a cell is at length 240 cm. On shunting the cell with a resistance of 2 Ω the balancing length becomes 120 cm. The internal resistance of the cell is

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a

4 Ω

b

2 Ω

c

1 Ω

d

0.5 Ω

answer is B.

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Detailed Solution

r=Rl1l2−1 =2 240120−1=2 Ω

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