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Questions  

In a process VT3 , temperature of one mole of a gas is increased by 200k work done by the gas in this process will be

a
600 R
b
800 R
c
1000 R
d
1200 R

detailed solution

Correct option is A

V  = KT3, dV = 3KT2dTW=∫PdV = ∫nRTVdV = ∫nRTV3kT2dT∫3nRdT = 3R200 = 600R

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