P-V curve of a diatomic gas is shown in the figure. Find the total heat given to the gas in the process A → B →C

From first law of thermodynamics∆QABC = ∆UABC + ∆WABC∆WABC = ∆WAB+∆WBC = 0 + nRTBln VCVB                 = nRTB ln 2V0V0               = nRTB ln 2 = 2P0V0 ln 2∆U = nCV∆T = 52(2P0V0-P0V0)⇒∆QABC = 52P0V0+2P0V0 ln 2